JEE Main 20241 Feb, Evening shiftMathematicsMediumIntegral Calculus369× since 2002Let f:(0,∞)→Rf:(0, \infty) \rightarrow \mathbf{R}f:(0,∞)→R and F(x)=∫0xtf(t)dt\mathrm{F}(x)=\int\limits_0^x \mathrm{t} f(\mathrm{t}) \mathrm{dt}F(x)=0∫xtf(t)dt. If F(x2)=x4+x5\mathrm{F}\left(x^2\right)=x^4+x^5F(x2)=x4+x5, then ∑r=112f(r2)\sum\limits_{\mathrm{r}=1}^{12} f\left(\mathrm{r}^2\right)r=1∑12f(r2) is equal to ____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
