MathematicsMedium129×since 2002Q5166Let α\alphaα and β\betaβ be the roots of the equation px2+qx−r=0p x^2+q x-r=0px2+qx−r=0, where p≠0p \neq 0p=0. If p,qp, qp,q and rrr be the consecutive terms of a non constant G.P. and 1α+1β=34\frac{1}{\alpha}+\frac{1}{\beta}=\frac{3}{4}α1+β1=43, then the value of (α−β)2(\alpha-\beta)^2(α−β)2 is :A8B9C203\frac{20}{3}320D809\frac{80}{9}980Check answerSkip