JEE Main 202621 Jan, Evening shiftMathematicsEasySets, Relations and Functions168× since 2002Let A={x:∣x2−10∣≤6}A=\{x : |x^2-10|\le 6\}A={x:∣x2−10∣≤6} and B={x:∣x−2∣>1}B=\{x : |x-2|>1\}B={x:∣x−2∣>1}. ThenAOption A. A−B=[2,3)A-B=[2, 3)A−B=[2,3)BOption B. B−A=(−∞,−4)∪(−2,1)∪(4,∞)B-A=(-\infty, -4)\cup(-2, 1)\cup(4, \infty)B−A=(−∞,−4)∪(−2,1)∪(4,∞)COption C. A∪B=(−∞,1]∪(2,∞)A\cup B=(-\infty, 1]\cup(2, \infty)A∪B=(−∞,1]∪(2,∞)DOption D. A∩B=[−4,−2]∪[3,4]A\cap B=[-4, -2]\cup[3, 4]A∩B=[−4,−2]∪[3,4]CheckSkip · show solution
