JEE Main 20264 Apr, Morning shiftMathematicsEasyMatrices and Determinants245× since 2002Let A=[112−201135]A=\begin{bmatrix}1&1&2\\-2&0&1\\1&3&5\end{bmatrix}A=1−21103215. Then the sum of all elements of the matrix adj(adj(2(adjA)−1))\operatorname{adj}(\operatorname{adj}(2(\operatorname{adj}A)^{-1}))adj(adj(2(adjA)−1)) is equal to:AOption A. 3BOption B. 4COption C. −4-4−4DOption D. −3-3−3CheckSkip · show solution
