MathematicsEasy129×since 2002Q5057Let a, b ∈\in∈ R be such that the equation ax2−2bx+15=0a{x^2} - 2bx + 15 = 0ax2−2bx+15=0 has a repeated root α\alphaα. If α\alphaα and β\betaβ are the roots of the equation x2−2bx+21=0{x^2} - 2bx + 21 = 0x2−2bx+21=0, then α2+β2{\alpha ^2} + {\beta ^2}α2+β2 is equal to :A37B58C68D92Check answerSkip