MathematicsMedium64×since 2004Q3998∫{(logx−1)1+(logx)2}2 dx\int {{{\left\{ {{{\left( {\log x - 1} \right)} \over {1 + {{\left( {\log x} \right)}^2}}}} \right\}}^2}\,\,dx}∫{1+(logx)2(logx−1)}2dx is equal toAlogx(logx)2+1+C{{\log x} \over {{{\left( {\log x} \right)}^2} + 1}} + C(logx)2+1logx+CBxx2+1+C{x \over {{x^2} + 1}} + Cx2+1x+CCxex1+x2+C{{x{e^x}} \over {1 + {x^2}}} + C1+x2xex+CDx(logx)2+1+C{x \over {{{\left( {\log x} \right)}^2} + 1}} + C(logx)2+1x+CCheck answerSkip