PhysicsHard120×since 2002Q6829In the given electromagnetic wave Ey=600sin(ωt−kx)Vm−1\mathrm{E}_{\mathrm{y}}=600 \sin (\omega t-\mathrm{kx}) \mathrm{Vm}^{-1}Ey=600sin(ωt−kx)Vm−1, intensity of the associated light beam is (in W/m2\mathrm{W} / \mathrm{m}^2W/m2 : (Given ϵ0=9×10−12C2 N−1 m−2\epsilon_0=9 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}ϵ0=9×10−12C2 N−1 m−2 )A486B729C243D972Check answerSkip