PC l₅ (g) → PC l₃ (g) + C l₂ (g) In the above first order reaction the concentration of PCl₅ reduces from initial concentration 50 mol L⁻¹ to 10 mol L⁻¹ in 120 minutes at 300 K. The rate constant for the reaction at 300 K is x × 10⁻² min⁻¹. The value of x is _ _ _ _ _. [Given log5 = 0.6989]

Chemical Kinetics: JEE Main 2021 Chemistry question

JEE Main 2021 · 20 Jul, Evening shift · Q4

JEE Main 202120 Jul, Evening shiftChemistryMediumChemical Kinetics62× since 2002

PC{l_5}(g) \to PC{l_3}(g) + C{l_2}(g)

In the above first order reaction the concentration of PCl₅ reduces from initial concentration 50 mol L^

-

1 to 10 mol L^

-

1 in 120 minutes at 300 K. The rate constant for the reaction at 300 K is x

\times

10^

-

2 min^

-

1. The value of x is __________. [Given log5 = 0.6989]

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Chemical Kinetics Question with Answer (20 Jul Evening shift, Q4) | JEE Arc