In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf 1.5 ~V is found to be 60 ~cm. If this cell is replaced by another cell of emf E, the length-of null point increases by 40 ~cm. The value of E is x/10 V. The value of x is _ _ _ _ _ _.

Current Electricity: JEE Main 2023 Physics question

JEE Main 2023 · 1 Feb, Morning shift · Q54

JEE Main 20231 Feb, Morning shiftPhysicsMediumCurrent Electricity150× since 2002

In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf

1.5 \mathrm{~V}

is found to be

60 \mathrm{~cm}

. If this cell is replaced by another cell of emf E, the length-of null point increases by

40 \mathrm{~cm}

. The value of

E

\frac{x}{10} V

. The value of

x

is ____________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2023 Current Electricity Question with Answer (1 Feb Morning shift, Q54) | JEE Arc

JEE Main 2023 · 1 Feb, Morning shift · Q54

JEE Main 20231 Feb, Morning shiftPhysicsMediumCurrent Electricity150× since 2002

In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf

1.5 \mathrm{~V}

is found to be

60 \mathrm{~cm}

. If this cell is replaced by another cell of emf E, the length-of null point increases by

40 \mathrm{~cm}

. The value of

E

\frac{x}{10} V

. The value of

x

is ____________.

Your answerType your answer. Integers and decimals are accepted.