MathematicsMedium129×since 2002Q5116In a triangle PQR, ∠R=π2. If tan (P2)PQR,\;\;\angle R = {\pi \over 2}.\,\,If\,\,\tan \,\left( {{P \over 2}} \right)PQR,∠R=2π.Iftan(2P) and tan(Q2)\tan \left( {{Q \over 2}} \right)tan(2Q) are the roots of ax2+bx+c=0, a≠0a{x^2} + bx + c = 0,\,\,a \ne 0ax2+bx+c=0,a=0 thenAa=b+ca = b + ca=b+cBc=a+bc = a + bc=a+bCb=cb = cb=cDb=a+cb = a + cb=a+cCheck answerSkip