PhysicsMedium120×since 2002Q6822In a plane EM wave, the electric field oscillates sinusoidally at a frequency of 5×1010 Hz5 \times 10^{10} \mathrm{~Hz}5×1010 Hz and an amplitude of 50 Vm−150 \mathrm{~Vm}^{-1}50 Vm−1. The total average energy density of the electromagnetic field of the wave is : [Use ε0=8.85×10−12C2/Nm2\varepsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 / \mathrm{Nm}^2ε0=8.85×10−12C2/Nm2 ]A4.425×10−8Jm−34.425 \times 10^{-8} \mathrm{Jm}^{-3}4.425×10−8Jm−3B2.212×10−10Jm−32.212 \times 10^{-10} \mathrm{Jm}^{-3}2.212×10−10Jm−3C2.212×10−8Jm−32.212 \times 10^{-8} \mathrm{Jm}^{-3}2.212×10−8Jm−3D1.106×10−8Jm−31.106 \times 10^{-8} \mathrm{Jm}^{-3}1.106×10−8Jm−3Check answerSkip