MathematicsMedium64×since 2004Q4051If ƒ'(x) = tan^–1(secx + tanx), −π2<x<π2- {\pi \over 2} < x < {\pi \over 2}−2π<x<2π, and ƒ(0) = 0, then ƒ(1) is equal to :A14{1 \over 4}41Bπ−14{{\pi - 1} \over 4}4π−1Cπ+14{{\pi + 1} \over 4}4π+1Dπ+24{{\pi + 2} \over 4}4π+2Check answerSkip