MathematicsEasy63×since 2002Q3685If x=ey+ey+ey+.....∞x = {e^{y + {e^y} + {e^{y + .....\infty }}}}x=ey+ey+ey+.....∞ , x>0,x > 0,x>0, then dydx{{{dy} \over {dx}}}dxdy isA1+xx{{1 + x} \over x}x1+xB1x{1 \over x}x1C1−xx{{1 - x} \over x}x1−xDx1+x{x \over {1 + x}}1+xxCheck answerSkip