MathematicsEasy129×since 2002Q5062If [x] be the greatest integer less than or equal to x, then ∑n=8100[(−1)nn2]\sum\limits_{n = 8}^{100} {\left[ {{{{{( - 1)}^n}n} \over 2}} \right]}n=8∑100[2(−1)nn] is equal to :A0B4C−-−2D2Check answerSkip