JEE Main 202226 Jun, Evening shiftMathematicsMediumComplex Numbers and Quadratic Equations264× since 2002If z2+z+1=0{z^2} + z + 1 = 0z2+z+1=0, z∈Cz \in Cz∈C, then ∣∑n=115(zn+(−1)n1zn)2∣\left| {\sum\limits_{n = 1}^{15} {{{\left( {{z^n} + {{( - 1)}^n}{1 \over {{z^n}}}} \right)}^2}} } \right|n=1∑15(zn+(−1)nzn1)2 is equal to _________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
