MathematicsMedium63×since 2002Q3692If 2xy+3yx=202 x^{y}+3 y^{x}=202xy+3yx=20, then dydx\frac{d y}{d x}dxdy at (2,2)(2,2)(2,2) is equal to :A−(3+loge164+loge8)-\left(\frac{3+\log _{e} 16}{4+\log _{e} 8}\right)−(4+loge83+loge16)B−(2+loge83+loge4)-\left(\frac{2+\log _{e} 8}{3+\log _{e} 4}\right)−(3+loge42+loge8)C−(3+loge82+loge4)-\left(\frac{3+\log _{e} 8}{2+\log _{e} 4}\right)−(2+loge43+loge8)D−(3+loge42+loge8)-\left(\frac{3+\log _{e} 4}{2+\log _{e} 8}\right)−(2+loge83+loge4)Check answerSkip