MathematicsMedium127×since 2002Q3134If the tangents drawn at the points O(0,0)O(0,0)O(0,0) and P(1+5,2)P\left( {1 + \sqrt 5 ,2} \right)P(1+5,2) on the circle x2+y2−2x−4y=0{x^2} + {y^2} - 2x - 4y = 0x2+y2−2x−4y=0 intersect at the point Q, then the area of the triangle OPQ is equal to :A3+52{{3 + \sqrt 5 } \over 2}23+5B4+252{{4 + 2\sqrt 5 } \over 2}24+25C5+352{{5 + 3\sqrt 5 } \over 2}25+35D7+352{{7 + 3\sqrt 5 } \over 2}27+35Check answerSkip