If the solubility product of PbS is 8 × 10⁻²8, then the solubility of PbS in pure water at 298 K is x × 10⁻¹6 mol L⁻¹. The value of x is _ _ _ _ _. (Nearest Integer) [Given: 2 = 1.41]

Equilibrium: JEE Main 2022 Chemistry question

JEE Main 2022 · 29 Jul, Morning shift · Q11

JEE Main 202229 Jul, Morning shiftChemistryMediumEquilibrium123× since 2002

If the solubility product of PbS is 8

\times

10^

-

28, then the solubility of PbS in pure water at 298 K is x

\times

10^

-

16 mol L^

-

1. The value of x is __________. (Nearest Integer) [Given :

\sqrt2

= 1.41]

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2022 Equilibrium Question with Answer (29 Jul Morning shift, Q11) | JEE Arc