JEE Main 202324 Jan, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002If the shortest between the lines x+62=y−63=z−64{{x + \sqrt 6 } \over 2} = {{y - \sqrt 6 } \over 3} = {{z - \sqrt 6 } \over 4}2x+6=3y−6=4z−6 and x−λ3=y−264=z+265{{x - \lambda } \over 3} = {{y - 2\sqrt 6 } \over 4} = {{z + 2\sqrt 6 } \over 5}3x−λ=4y−26=5z+26 is 6, then the square of sum of all possible values of λ\lambdaλ is :Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
