JEE Main 20264 Apr, Morning shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002If the set of all solutions of ∣x2+x−9∣=∣x∣+∣x2−9∣|x^2+x-9|=|x|+|x^2-9|∣x2+x−9∣=∣x∣+∣x2−9∣ is [α,β]∪[γ,∞)[\alpha, \beta]\cup[\gamma, \infty)[α,β]∪[γ,∞), then (α2+β2+γ2)(\alpha^2+\beta^2+\gamma^2)(α2+β2+γ2) is equal to:AOption A. 9BOption B. 18COption C. 36DOption D. 72CheckSkip · show solution
