Integral Calculus: JEE Main 2021 Mathematics question

JEE Main 2021 · 16 Mar, Morning shift · Q31

JEE Main 202116 Mar, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

If the normal to the curve y(x) =

\int\limits_0^x {(2{t^2} - 15t + 10)dt}

at a point (a, b) is parallel to the line x + 3y =

-

5, a > 1, then the value of | a + 6b | is equal to ___________.

Your answerType your answer. Integers and decimals are accepted.

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JEE Main 2021 Integral Calculus Question with Answer (16 Mar Morning shift, Q31) | JEE Arc

JEE Main 2021 · 16 Mar, Morning shift · Q31

JEE Main 202116 Mar, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

If the normal to the curve y(x) =

\int\limits_0^x {(2{t^2} - 15t + 10)dt}

at a point (a, b) is parallel to the line x + 3y =

-

5, a > 1, then the value of | a + 6b | is equal to ___________.

Your answerType your answer. Integers and decimals are accepted.