JEE Main 202125 Jul, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002If the lines x−k1=y−22=z−33{{x - k} \over 1} = {{y - 2} \over 2} = {{z - 3} \over 3}1x−k=2y−2=3z−3 and x+13=y+22=z+31{{x + 1} \over 3} = {{y + 2} \over 2} = {{z + 3} \over 1}3x+1=2y+2=1z+3 are co-planar, then the value of k is _____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution