JEE Main 202311 Apr, Evening shiftMathematicsMediumCoordinate Geometry478× since 2002If the line l1:3y−2x=3l_{1}: 3 y-2 x=3l1:3y−2x=3 is the angular bisector of the lines l2:x−y+1=0l_{2}: x-y+1=0l2:x−y+1=0 and l3:αx+βy+17=0l_{3}: \alpha x+\beta y+17=0l3:αx+βy+17=0, then α2+β2−α−β\alpha^{2}+\beta^{2}-\alpha-\betaα2+β2−α−β is equal to _________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
