If the function f(x) = (eˣ(e^(tan x - x) - 1) + log e (sec x + tan x) - x)/(tan x - x) is continuous at x = 0, then the value of f(0) is equal to

Limit, Continuity and Differentiability: JEE Main 2026 Mathematics question

JEE Main 2026 · 24 Jan, Morning shift · Q7

JEE Main 202624 Jan, Morning shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002

If the function

f(x) = \frac{e^x\left(e^{\tan x - x} - 1\right) + \log_e(\sec x + \tan x) - x}{\tan x - x}

is continuous at

x = 0

, then the value of

f(0)

is equal to