JEE Main 20266 Apr, Morning shiftChemistryEasyAtomic Structure113× since 2002If shortest wavelength of hydrogen atom in Lyman series is xxx, then longest wavelength in Balmer series of He+\mathrm{He^+}He+ is:AOption A. 9x5\frac{9x}{5}59xBOption B. 36x5\frac{36x}{5}536xCOption C. x4\frac x44xDOption D. 5x9\frac{5x}{9}95xCheckSkip · show solution
