If one of the diameters of the circle x² + y² - 2 2 x - 6 2 y + 14 = 0 is a chord of the circle (x - 2 2)² + (y - 2 2)² = r², then the value of r² is equal to _ _ _ _ _ _.

Coordinate Geometry: JEE Main 2022 Mathematics question

JEE Main 2022 · 28 Jun, Evening shift · Q26

JEE Main 202228 Jun, Evening shiftMathematicsMediumCoordinate Geometry478× since 2002

If one of the diameters of the circle

{x^2} + {y^2} - 2\sqrt 2 x - 6\sqrt 2 y + 14 = 0

is a chord of the circle

{(x - 2\sqrt 2 )^2} + {(y - 2\sqrt 2 )^2} = {r^2}

, then the value of r² is equal to ____________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2022 · 28 Jun, Evening shift · Q26

JEE Main 202228 Jun, Evening shiftMathematicsMediumCoordinate Geometry478× since 2002

If one of the diameters of the circle

{x^2} + {y^2} - 2\sqrt 2 x - 6\sqrt 2 y + 14 = 0

is a chord of the circle

{(x - 2\sqrt 2 )^2} + {(y - 2\sqrt 2 )^2} = {r^2}

, then the value of r² is equal to ____________.

Your answerType your answer. Integers and decimals are accepted.