MathematicsMedium127×since 2002Q3043If one of the diameters of the circle, given by the equation, x2+y2−4x+6y−12=0,{x^2} + {y^2} - 4x + 6y - 12 = 0,x2+y2−4x+6y−12=0, is a chord of a circle SSS, whose centre is at (−3,2)(-3, 2)(−3,2), then the radius of SSS is :A555B101010C525\sqrt 252D535\sqrt 353Check answerSkip