JEE Main 20264 Apr, Evening shiftMathematicsEasyThree Dimensional Geometry249× since 2002If (2α+1, α2−3α, α−12)\left(2\alpha+1,\ \alpha^2-3\alpha,\ \frac{\alpha-1}{2}\right)(2α+1, α2−3α, 2α−1) is the image of (α,2α,1)(\alpha, 2\alpha, 1)(α,2α,1) in the line x−23=y−12=z1\frac{x-2}{3}=\frac{y-1}{2}=\frac z13x−2=2y−1=1z, then the possible value(s) of α\alphaα is (are)AOption A. Only 3BOption B. Only 3 and −1-1−1COption C. Only 3, 14\frac1441 and −1-1−1DOption D. Only 3 and 14\frac1441CheckSkip · show solution
