JEE Main 202529 Jan, Evening shiftChemistryMediumChemical Thermodynamics84× since 2002If C(diamond)→C(graphite)\mathrm{C(diamond) \rightarrow C(graphite)}C(diamond)→C(graphite) + X kJ mol−1\mathrm{mol^{-1}}mol−1, C(diamond)+O2(g)→CO2(g)\mathrm{C(diamond) + O_2(g) \rightarrow CO_2(g)}C(diamond)+O2(g)→CO2(g) + Y kJ mol−1\mathrm{mol^{-1}}mol−1, C(graphite)+O2(g)→CO2(g)\mathrm{C(graphite) + O_2(g) \rightarrow CO_2(g)}C(graphite)+O2(g)→CO2(g) + Z kJ mol−1\mathrm{mol^{-1}}mol−1 at constant temperature. ThenAOption A. X = Y − ZBOption B. X = Y + ZCOption C. X = −Y + ZDOption D. −X = Y + ZCheckSkip · show solution
