JEE Main 20241 Feb, Morning shiftMathematicsMediumDifferential Equations163× since 2002If x=x(t)x=x(t)x=x(t) is the solution of the differential equation (t+1)dx=(2x+(t+1)4)dt,x(0)=2(t+1) \mathrm{d} x=\left(2 x+(t+1)^4\right) \mathrm{dt}, x(0)=2(t+1)dx=(2x+(t+1)4)dt,x(0)=2, then, x(1)x(1)x(1) equals _________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
