JEE Main 202622 Jan, Evening shiftMathematicsMediumMatrices and Determinants245× since 2002If X=[xyz]X=\begin{bmatrix} x\\ y\\ z\end{bmatrix}X=xyz is a solution of the system of equations AX=BAX=BAX=B, where adj A=[422−5051−23]\mathrm{adj}\,A=\begin{bmatrix} 4 & 2 & 2\\ -5 & 0 & 5\\ 1 & -2 & 3\end{bmatrix}adjA=4−5120−2253 and B=[402]B=\begin{bmatrix} 4\\ 0\\ 2\end{bmatrix}B=402, then ∣x+y+z∣|x+y+z|∣x+y+z∣ is equal to :AOption A. 1BOption B. 3COption C. 2DOption D. 32\frac{3}{2}23CheckSkip · show solution
