MathematicsMedium64×since 2004Q4053If ∫(x2+1)ex(x+1)2dx=f(x)ex+C\int {{{({x^2} + 1){e^x}} \over {{{(x + 1)}^2}}}dx = f(x){e^x} + C}∫(x+1)2(x2+1)exdx=f(x)ex+C, where C is a constant, then d3fdx3{{{d^3}f} \over {d{x^3}}}dx3d3f at x = 1 is equal to :A−34- {3 \over 4}−43B34{3 \over 4}43C−32- {3 \over 2}−23D32{3 \over 2}23Check answerSkip