MathematicsMedium64×since 2004Q4017If ∫1−x2x4\int {{{\sqrt {1 - {x^2}} } \over {{x^4}}}}∫x41−x2 dx = A(x)(1−x2)m{\left( {\sqrt {1 - {x^2}} } \right)^m}(1−x2)m + C, for a suitable chosen integer m and a function A(x), where C is a constant of integration, then (A(x))^m equals :A127x6{1 \over {27{x^6}}}27x61B−127x9{{ - 1} \over {27{x^9}}}27x9−1C19x4{1 \over {9{x^4}}}9x41D13x3{1 \over {3{x^3}}}3x31Check answerSkip