JEE Main 202127 Aug, Morning shiftMathematicsMediumIntegral Calculus369× since 2002If ∫dx(x2+x+1)2=atan−1(2x+13)+b(2x+1x2+x+1)+C\int {{{dx} \over {{{({x^2} + x + 1)}^2}}} = a{{\tan }^{ - 1}}\left( {{{2x + 1} \over {\sqrt 3 }}} \right) + b\left( {{{2x + 1} \over {{x^2} + x + 1}}} \right) + C}∫(x2+x+1)2dx=atan−1(32x+1)+b(x2+x+12x+1)+C, x > 0 where C is the constant of integration, then the value of 9(3a+b)9\left( {\sqrt 3 a + b} \right)9(3a+b) is equal to _____________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution