JEE Main 202628 Jan, Morning shiftMathematicsEasyTrigonometry118× since 2002If tan(A−B)tanA+sin2Csin2A=1\frac{\tan(A-B)}{\tan A}+\frac{\sin^2C}{\sin^2A}=1tanAtan(A−B)+sin2Asin2C=1, A,B,C∈(0,π2)A,B,C\in\left(0,\frac{\pi}{2}\right)A,B,C∈(0,2π), thenAOption A. tan A, tan B, tan C are in G.P.BOption B. tan A, tan C, tan B are in G.P.COption C. tan A, tan B, tan C are in A.P.DOption D. tan A, tan C, tan B are in A.P.CheckSkip · show solution
