If for some α > 0, the area of the region (x,y):|x + α | ≤ y ≤ 2 - |x| is equal to 3/2, then the area of the region (x,y):0 ≤ y ≤ x + 2α, |x| ≤ 1 is equal to _ _ _ _ _ _.

Integral Calculus: JEE Main 2022 Mathematics question

JEE Main 2022 · 30 Jun, Morning shift · Q24

JEE Main 202230 Jun, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

If for some

\alpha

> 0, the area of the region

\{ (x,y):|x + \alpha | \le y \le 2 - |x|\}

is equal to

{3 \over 2}

, then the area of the region

\{ (x,y):0 \le y \le x + 2\alpha ,\,|x| \le 1\}

is equal to ____________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2022 Integral Calculus Question with Answer (30 Jun Morning shift, Q24) | JEE Arc