MathematicsHard129×since 2002Q5059If a∈Ra \in Ra∈R and the equation −3(x−[x])2+2(x−[x])+a2=0- 3{\left( {x - \left[ x \right]} \right)^2} + 2\left( {x - \left[ x \right]} \right) + {a^2} = 0−3(x−[x])2+2(x−[x])+a2=0 (where [xxx] denotes the greater integer ≤x\le x≤x) has no integral solution, then all possible values of a lie in the interval :A(−2,−1)\left( { - 2, - 1} \right)(−2,−1)B(−∞,−2)∪(2,∞)\left( { - \infty , - 2} \right) \cup \left( {2,\infty } \right)(−∞,−2)∪(2,∞)C(−1,0)∪(0,1)\left( { - 1,0} \right) \cup \left( {0,1} \right)(−1,0)∪(0,1)D(1,2)\left( {1,2} \right)(1,2)Check answerSkip