MathematicsMedium129×since 2002Q5138If α\alphaα and β\betaβ be two roots of the equation x² – 64x + 256 = 0. Then the value of (α3β5)1/8+(β3α5)1/8{\left( {{{{\alpha ^3}} \over {{\beta ^5}}}} \right)^{1/8}} + {\left( {{{{\beta ^3}} \over {{\alpha ^5}}}} \right)^{1/8}}(β5α3)1/8+(α5β3)1/8 is :A1B3C2D4Check answerSkip