MathematicsMedium129×since 2002Q5151If α\alphaα and β\betaβ are the distinct roots of the equation x2+(3)1/4x+31/2=0{x^2} + {(3)^{1/4}}x + {3^{1/2}} = 0x2+(3)1/4x+31/2=0, then the value of α96(α12−1)+β96(β12−1){\alpha ^{96}}({\alpha ^{12}} - 1) + {\beta ^{96}}({\beta ^{12}} - 1)α96(α12−1)+β96(β12−1) is equal to :A56 ×\times× 3²⁵B56 ×\times× 3²⁴C52 ×\times× 3²⁴D28 ×\times× 3²⁵Check answerSkip