JEE Main 20264 Apr, Morning shiftMathematicsMediumTrigonometry118× since 2002If A=sin3∘cos9∘+sin9∘cos27∘+sin27∘cos81∘A=\frac{\sin3^\circ}{\cos9^\circ}+\frac{\sin9^\circ}{\cos27^\circ}+\frac{\sin27^\circ}{\cos81^\circ}A=cos9∘sin3∘+cos27∘sin9∘+cos81∘sin27∘ and B=tan81∘−tan3∘B=\tan81^\circ-\tan3^\circB=tan81∘−tan3∘, then BA\frac{B}{A}AB is equal to ______.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
