MathematicsMedium127×since 2002Q3104If a circle passes through the point (a, b) and cuts the circle x2 + y2=p2{x^2}\, + \,{y^2} = {p^2}x2+y2=p2 orthogonally, then the equation of the locus of its centre is :Ax2 + y2− 3ax − 4 by + (a2 + b2−p2)=0{x^2}\, + \,{y^2} - \,3ax\, - \,4\,by\,\, + \,({a^2}\, + \,{b^2} - {p^2}) = 0x2+y2−3ax−4by+(a2+b2−p2)=0B2ax + 2 by − (a2 − b2+p2)=02ax\, + \,\,2\,by\,\, - \,({a^2}\, - \,{b^2} + {p^2}) = 02ax+2by−(a2−b2+p2)=0Cx2 + y2− 2ax − 3 by + (a2 − b2−p2)=0{x^2}\, + \,{y^2} - \,2ax\, - \,\,3\,by\,\, + \,({a^2}\, - \,{b^2} - {p^2}) = 0x2+y2−2ax−3by+(a2−b2−p2)=0D2ax + 2 by − (a2 + b2+p2)=02ax\, + \,\,2\,by\,\, - \,({a^2}\, + \,{b^2} + {p^2}) = 02ax+2by−(a2+b2+p2)=0Check answerSkip