MathematicsMedium127×since 2002Q3080If a circle of radius R passes through the origin O and intersects the coordinates axes at A and B, then the locus of the foot of perpendicular from O on AB is :A(x² + y²)² = 4R²x²y²B(x² + y²) (x + y) = R²xyC(x² + y²)² = 4Rx²y²D(x² + y²)³ = 4R²x²y²Check answerSkip