JEE Main 202124 Feb, Evening shiftMathematicsMediumSets, Relations and Functions168× since 2002If a + α\alphaα = 1, b + β\betaβ = 2 and af(x)+αf(1x)=bx+βx,x≠0af(x) + \alpha f\left( {{1 \over x}} \right) = bx + {\beta \over x},x \ne 0af(x)+αf(x1)=bx+xβ,x=0, then the value of the expression f(x)+f(1x)x+1x{{f(x) + f\left( {{1 \over x}} \right)} \over {x + {1 \over x}}}x+x1f(x)+f(x1) is __________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution