MathematicsHard129×since 2002Q5170If 2 and 6 are the roots of the equation ax2+bx+1=0a x^2+b x+1=0ax2+bx+1=0, then the quadratic equation, whose roots are 12a+b\frac{1}{2 a+b}2a+b1 and 16a+b\frac{1}{6 a+b}6a+b1, is :Ax2+8x+12=0x^2+8 x+12=0x2+8x+12=0B2x2+11x+12=02 x^2+11 x+12=02x2+11x+12=0C4x2+14x+12=04 x^2+14 x+12=04x2+14x+12=0Dx2+10x+16=0x^2+10 x+16=0x2+10x+16=0Check answerSkip