Given: Δ H^ sub [C (graphite)] = 710 kJ mol ⁻¹ Δ C-H H^ = 414 kJ mol ⁻¹ Δ H-H H^ = 436 kJ mol ⁻¹ Δ C=C H^ = 611 kJ mol ⁻¹ The Δ H f ^ for CH₂=CH₂ is _ _ _ kJ mol ⁻¹ (nearest integer value)

Chemical Thermodynamics: JEE Main 2025 Chemistry question

JEE Main 2025 · 3 Apr, Morning shift · Q75

JEE Main 20253 Apr, Morning shiftChemistryMediumChemical Thermodynamics84× since 2002

Given :

\Delta H^\ominus_{\text{sub}}

[C (graphite)] = 710 kJ mol

^{-1}

\Delta_{\text{C-H}}H^\ominus

= 414 kJ mol

^{-1}

\Delta_{\text{H-H}}H^\ominus

= 436 kJ mol

^{-1}

\Delta_{\text{C=C}}H^\ominus

= 611 kJ mol

^{-1}

The

\Delta H_f^\ominus

for

\mathrm{CH_2=CH_2}

is ______ kJ mol

^{-1}

(nearest integer value)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2025 Chemical Thermodynamics Question with Solution (3 Apr Morning shift, Q75) | JEE Arc