Given at 298 K: E^ _ Fe²⁺/Fe =X Volt, E^ _ Fe³⁺/Fe =Y Volt. The E^ _ Fe³⁺/Fe²⁺ in Volt at 298 K is given by:

Redox Reactions and Electrochemistry: JEE Main 2026 Chemistry question

JEE Main 2026 · 8 Apr, Evening shift · Q56

JEE Main 20268 Apr, Evening shiftChemistryEasyRedox Reactions and Electrochemistry138× since 2002

Given at 298 K :

E^\ominus_{\mathrm{Fe^{2+}/Fe}}=X

Volt,

E^\ominus_{\mathrm{Fe^{3+}/Fe}}=Y

Volt. The

E^\ominus_{\mathrm{Fe^{3+}/Fe^{2+}}}

in Volt at 298 K is given by :

JEE Main 2026 · 8 Apr, Evening shift · Q56

JEE Main 20268 Apr, Evening shiftChemistryEasyRedox Reactions and Electrochemistry138× since 2002

Given at 298 K :

E^\ominus_{\mathrm{Fe^{2+}/Fe}}=X

Volt,

E^\ominus_{\mathrm{Fe^{3+}/Fe}}=Y

Volt. The

E^\ominus_{\mathrm{Fe^{3+}/Fe^{2+}}}

in Volt at 298 K is given by :