MathematicsMedium127×since 2002Q3114Four distinct points (2k,3k),(1,0),(0,1)(2 k, 3 k),(1,0),(0,1)(2k,3k),(1,0),(0,1) and (0,0)(0,0)(0,0) lie on a circle for kkk equal to :A313\frac{3}{13}133B213\frac{2}{13}132C513\frac{5}{13}135D113\frac{1}{13}131Check answerSkip