For the reaction: A(l) → 2B(g) Δ U = 2.1 kcal, Δ S = 20 cal K⁻¹ at 300 K Hence Δ G in kcal is:

Chemical Thermodynamics: JEE Main 2020 Chemistry question

JEE Main 2020 · 7 Jan, Morning shift · Q20

JEE Main 20207 Jan, Morning shiftChemistryMediumChemical Thermodynamics84× since 2002

For the reaction : A(

l

)

\to

2B(g)

\Delta U = 2.1\,kcal,\,\Delta S = 20\,cal\,{K^{ - 1}}

at 300 K Hence

\Delta

G in kcal is :

Your answerType your answer. Integers and decimals are accepted.