For the given reactions Sn²⁺ + 2e^ - → Sn Sn⁴⁺ + 4e^ - → Sn the electrode potentials are; E_ S n²⁺ /Sn ^(o) = - 0.140 V and E_ S n⁴⁺ /Sn ^(o) = + 0.010 V. The magnitude of standard electrode potential for S n⁴⁺ /S n²⁺ i.e. E_ S n⁴⁺ /S n²⁺ ^(o) is _ _ _ _ _ _ _ × 10⁻² V. (Nearest integer)

Redox Reactions and Electrochemistry: JEE Main 2022 Chemistry question

JEE Main 2022 · 28 Jun, Evening shift · Q6

JEE Main 202228 Jun, Evening shiftChemistryHardRedox Reactions and Electrochemistry138× since 2002

For the given reactions Sn²⁺ + 2e^

-

\to

Sn Sn⁴⁺ + 4e^

-

\to

Sn the electrode potentials are ;

E_{S{n^{2 + }}/Sn}^o = - 0.140

V and

E_{S{n^{4 + }}/Sn}^o = + 0.010

V. The magnitude of standard electrode potential for

S{n^{4 + }}/S{n^{2 + }}

i.e.

E_{S{n^{4 + }}/S{n^{2 + }}}^o

is _____________

\times

10^

-

2 V. (Nearest integer)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2022 Redox Reactions and Electrochemistry Question with Answer (28 Jun Evening shift, Q6) | JEE Arc