Equilibrium: JEE Main 2026 Chemistry question

JEE Main 2026 · 4 Apr, Evening shift · Q72

JEE Main 20264 Apr, Evening shiftChemistryHardEquilibrium123× since 2002

For the following reaction at 50 °C and at 2 atm pressure,

\mathrm{2N_2O_5(g)\rightleftharpoons2N_2O_4(g)+O_2(g)}

\mathrm{N_2O_5}

is 50% dissociated. The magnitude of standard free energy change at this temperature is

x

x=

______ J mol

^{-1}

[Nearest integer]. Given:

R=8.314

J mol

^{-1}

^{-1}

, log 2 = 0.30, log 3 = 0.48, ln10 = 2.303, °C + 273 = K

Your answerType your answer. Integers and decimals are accepted.

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